During a sale, 7 rings and 11 bracelets cost $812. If Tiffany bought 5 rings and 3 bracelets, she would have spent all her money. Each ring cost $62 more than a bracelet. Find the amount that Tiffany had at first.
| |
Case 1 |
Case 2 |
| |
Rings |
Bracelets |
Rings |
Bracelets |
| Number |
7 |
11 |
5 |
3 |
| Value |
1 u + 62 |
1 u |
1 u + 62 |
1 u |
| Total value |
7 u + 434 |
11 u |
5 u + 310 |
3 u |
Cost of 1 bracelet = 1 u
Cost of 11 bracelets = 11 u
Cost of 1 ring = 1 u + 62
Cost of 7 rings = 7 x (1 u + 62) = 7 u + 434
Total cost of 11 bracelets and 7 rings
= 11 u + 7 u + 434
= 18 u + 434
18 u + 434 = 812
18 u = 812 - 434
18 u = 378
1 u = 378 ÷ 18 = 21
Cost of 5 rings = 5(1 u + 62) = 5 u + 310
Cost of 3 bracelets = 3 u
Amount that Tiffany had at first
= 5 u + 310 + 3 u
= 8 u + 310
= 8 x 21 + 310
= $478
Answer(s): $478
