During a sale, 8 rings and 4 necklaces cost $1260. If Roshel bought 6 rings and 3 necklaces, she would have spent all her money. Each ring cost $84 more than a necklace. Find the amount that Roshel had at first.
| |
Case 1 |
Case 2 |
| |
Rings |
Necklaces |
Rings |
Necklaces |
| Number |
8 |
4 |
6 |
3 |
| Value |
1 u + 84 |
1 u |
1 u + 84 |
1 u |
| Total value |
8 u + 672 |
4 u |
6 u + 504 |
3 u |
Cost of 1 necklace = 1 u
Cost of 4 necklaces = 4 u
Cost of 1 ring = 1 u + 84
Cost of 8 rings = 8 x (1 u + 84) = 8 u + 672
Total cost of 4 necklaces and 8 rings
= 4 u + 8 u + 672
= 12 u + 672
12 u + 672 = 1260
12 u = 1260 - 672
12 u = 588
1 u = 588 ÷ 12 = 49
Cost of 6 rings = 6(1 u + 84) = 6 u + 504
Cost of 3 necklaces = 3 u
Amount that Roshel had at first
= 6 u + 504 + 3 u
= 9 u + 504
= 9 x 49 + 504
= $945
Answer(s): $945
