During a sale, 6 bracelets and 9 rings cost $1038. If Pamela bought 9 bracelets and 15 rings, she would have spent all her money. Each bracelet cost $23 more than a ring. Find the amount that Pamela had at first.
| |
Case 1 |
Case 2 |
| |
Bracelets |
Rings |
Bracelets |
Rings |
| Number |
6 |
9 |
9 |
15 |
| Value |
1 u + 23 |
1 u |
1 u + 23 |
1 u |
| Total value |
6 u + 138 |
9 u |
9 u + 207 |
15 u |
Cost of 1 ring = 1 u
Cost of 9 rings = 9 u
Cost of 1 bracelet = 1 u + 23
Cost of 6 bracelets = 6 x (1 u + 23) = 6 u + 138
Total cost of 9 rings and 6 bracelets
= 9 u + 6 u + 138
= 15 u + 138
15 u + 138 = 1038
15 u = 1038 - 138
15 u = 900
1 u = 900 ÷ 15 = 60
Cost of 9 bracelets = 9(1 u + 23) = 9 u + 207
Cost of 15 rings = 15 u
Amount that Pamela had at first
= 9 u + 207 + 15 u
= 24 u + 207
= 24 x 60 + 207
= $1647
Answer(s): $1647
