During a sale, 5 bracelets and 7 rings cost $727. If Hilda bought 8 bracelets and 12 rings, she would have spent all her money. Each bracelet cost $59 more than a ring. Find the amount that Hilda had at first.
| |
Case 1 |
Case 2 |
| |
Bracelets |
Rings |
Bracelets |
Rings |
| Number |
5 |
7 |
8 |
12 |
| Value |
1 u + 59 |
1 u |
1 u + 59 |
1 u |
| Total value |
5 u + 295 |
7 u |
8 u + 472 |
12 u |
Cost of 1 ring = 1 u
Cost of 7 rings = 7 u
Cost of 1 bracelet = 1 u + 59
Cost of 5 bracelets = 5 x (1 u + 59) = 5 u + 295
Total cost of 7 rings and 5 bracelets
= 7 u + 5 u + 295
= 12 u + 295
12 u + 295 = 727
12 u = 727 - 295
12 u = 432
1 u = 432 ÷ 12 = 36
Cost of 8 bracelets = 8(1 u + 59) = 8 u + 472
Cost of 12 rings = 12 u
Amount that Hilda had at first
= 8 u + 472 + 12 u
= 20 u + 472
= 20 x 36 + 472
= $1192
Answer(s): $1192
