During a sale, 4 rings and 8 bracelets cost $608. If Abi bought 14 rings and 15 bracelets, she would have spent all her money. Each ring cost $95 more than a bracelet. Find the amount that Abi had at first.
| |
Case 1 |
Case 2 |
| |
Rings |
Bracelets |
Rings |
Bracelets |
| Number |
4 |
8 |
14 |
15 |
| Value |
1 u + 95 |
1 u |
1 u + 95 |
1 u |
| Total value |
4 u + 380 |
8 u |
14 u + 1330 |
15 u |
Cost of 1 bracelet = 1 u
Cost of 8 bracelets = 8 u
Cost of 1 ring = 1 u + 95
Cost of 4 rings = 4 x (1 u + 95) = 4 u + 380
Total cost of 8 bracelets and 4 rings
= 8 u + 4 u + 380
= 12 u + 380
12 u + 380 = 608
12 u = 608 - 380
12 u = 228
1 u = 228 ÷ 12 = 19
Cost of 14 rings = 14(1 u + 95) = 14 u + 1330
Cost of 15 bracelets = 15 u
Amount that Abi had at first
= 14 u + 1330 + 15 u
= 29 u + 1330
= 29 x 19 + 1330
= $1881
Answer(s): $1881
