During a sale, 4 bracelets and 3 rings cost $942. If Dana bought 4 bracelets and 8 rings, she would have spent all her money. Each bracelet cost $71 more than a ring. Find the amount that Dana had at first.
| |
Case 1 |
Case 2 |
| |
Bracelets |
Rings |
Bracelets |
Rings |
| Number |
4 |
3 |
4 |
8 |
| Value |
1 u + 71 |
1 u |
1 u + 71 |
1 u |
| Total value |
4 u + 284 |
3 u |
4 u + 284 |
8 u |
Cost of 1 ring = 1 u
Cost of 3 rings = 3 u
Cost of 1 bracelet = 1 u + 71
Cost of 4 bracelets = 4 x (1 u + 71) = 4 u + 284
Total cost of 3 rings and 4 bracelets
= 3 u + 4 u + 284
= 7 u + 284
7 u + 284 = 942
7 u = 942 - 284
7 u = 658
1 u = 658 ÷ 7 = 94
Cost of 4 bracelets = 4(1 u + 71) = 4 u + 284
Cost of 8 rings = 8 u
Amount that Dana had at first
= 4 u + 284 + 8 u
= 12 u + 284
= 12 x 94 + 284
= $1412
Answer(s): $1412
