During a sale, 7 necklaces and 3 bracelets cost $1044. If Tiffany bought 5 necklaces and 8 bracelets, she would have spent all her money. Each necklace cost $92 more than a bracelet. Find the amount that Tiffany had at first.
| |
Case 1 |
Case 2 |
| |
Necklaces |
Bracelets |
Necklaces |
Bracelets |
| Number |
7 |
3 |
5 |
8 |
| Value |
1 u + 92 |
1 u |
1 u + 92 |
1 u |
| Total value |
7 u + 644 |
3 u |
5 u + 460 |
8 u |
Cost of 1 bracelet = 1 u
Cost of 3 bracelets = 3 u
Cost of 1 necklace = 1 u + 92
Cost of 7 necklaces = 7 x (1 u + 92) = 7 u + 644
Total cost of 3 bracelets and 7 necklaces
= 3 u + 7 u + 644
= 10 u + 644
10 u + 644 = 1044
10 u = 1044 - 644
10 u = 400
1 u = 400 ÷ 10 = 40
Cost of 5 necklaces = 5(1 u + 92) = 5 u + 460
Cost of 8 bracelets = 8 u
Amount that Tiffany had at first
= 5 u + 460 + 8 u
= 13 u + 460
= 13 x 40 + 460
= $980
Answer(s): $980
