During a sale, 9 necklaces and 6 bracelets cost $1629. If Xylia bought 4 necklaces and 15 bracelets, she would have spent all her money. Each necklace cost $86 more than a bracelet. Find the amount that Xylia had at first.
| |
Case 1 |
Case 2 |
| |
Necklaces |
Bracelets |
Necklaces |
Bracelets |
| Number |
9 |
6 |
4 |
15 |
| Value |
1 u + 86 |
1 u |
1 u + 86 |
1 u |
| Total value |
9 u + 774 |
6 u |
4 u + 344 |
15 u |
Cost of 1 bracelet = 1 u
Cost of 6 bracelets = 6 u
Cost of 1 necklace = 1 u + 86
Cost of 9 necklaces = 9 x (1 u + 86) = 9 u + 774
Total cost of 6 bracelets and 9 necklaces
= 6 u + 9 u + 774
= 15 u + 774
15 u + 774 = 1629
15 u = 1629 - 774
15 u = 855
1 u = 855 ÷ 15 = 57
Cost of 4 necklaces = 4(1 u + 86) = 4 u + 344
Cost of 15 bracelets = 15 u
Amount that Xylia had at first
= 4 u + 344 + 15 u
= 19 u + 344
= 19 x 57 + 344
= $1427
Answer(s): $1427
