During a sale, 5 necklaces and 4 bracelets cost $1280. If Hilda bought 12 necklaces and 8 bracelets, she would have spent all her money. Each necklace cost $130 more than a bracelet. Find the amount that Hilda had at first.
| |
Case 1 |
Case 2 |
| |
Necklaces |
Bracelets |
Necklaces |
Bracelets |
| Number |
5 |
4 |
12 |
8 |
| Value |
1 u + 130 |
1 u |
1 u + 130 |
1 u |
| Total value |
5 u + 650 |
4 u |
12 u + 1560 |
8 u |
Cost of 1 bracelet = 1 u
Cost of 4 bracelets = 4 u
Cost of 1 necklace = 1 u + 130
Cost of 5 necklaces = 5 x (1 u + 130) = 5 u + 650
Total cost of 4 bracelets and 5 necklaces
= 4 u + 5 u + 650
= 9 u + 650
9 u + 650 = 1280
9 u = 1280 - 650
9 u = 630
1 u = 630 ÷ 9 = 70
Cost of 12 necklaces = 12(1 u + 130) = 12 u + 1560
Cost of 8 bracelets = 8 u
Amount that Hilda had at first
= 12 u + 1560 + 8 u
= 20 u + 1560
= 20 x 70 + 1560
= $2960
Answer(s): $2960
