During a sale, 4 necklaces and 11 bracelets cost $1937. If Sabrina bought 7 necklaces and 5 bracelets, she would have spent all her money. Each necklace cost $128 more than a bracelet. Find the amount that Sabrina had at first.

	Case 1		Case 2
	Necklaces	Bracelets	Necklaces	Bracelets
Number	4	11	7	5
Value	1 u + 128	1 u	1 u + 128	1 u
Total value	4 u + 512	11 u	7 u + 896	5 u

Cost of 1 bracelet = 1 u
Cost of 11 bracelets = 11 u

Cost of 1 necklace = 1 u + 128
Cost of 4 necklaces = 4 x (1 u + 128) = 4 u + 512

Total cost of 11 bracelets and 4 necklaces
= 11 u + 4 u + 512
= 15 u + 512

15 u + 512 = 1937
15 u = 1937 - 512
15 u = 1425

1 u = 1425 ÷ 15 = 95

Cost of 7 necklaces = 7(1 u + 128) = 7 u + 896
Cost of 5 bracelets = 5 u

Amount that Sabrina had at first
= 7 u + 896 + 5 u
= 12 u + 896
= 12 x 95 + 896
= $2036

Answer(s): $2036