During a sale, 10 bracelets and 8 necklaces cost $1382. If Vanessa bought 7 bracelets and 13 necklaces, she would have spent all her money. Each bracelet cost $59 more than a necklace. Find the amount that Vanessa had at first.
| |
Case 1 |
Case 2 |
| |
Bracelets |
Necklaces |
Bracelets |
Necklaces |
| Number |
10 |
8 |
7 |
13 |
| Value |
1 u + 59 |
1 u |
1 u + 59 |
1 u |
| Total value |
10 u + 590 |
8 u |
7 u + 413 |
13 u |
Cost of 1 necklace = 1 u
Cost of 8 necklaces = 8 u
Cost of 1 bracelet = 1 u + 59
Cost of 10 bracelets = 10 x (1 u + 59) = 10 u + 590
Total cost of 8 necklaces and 10 bracelets
= 8 u + 10 u + 590
= 18 u + 590
18 u + 590 = 1382
18 u = 1382 - 590
18 u = 792
1 u = 792 ÷ 18 = 44
Cost of 7 bracelets = 7(1 u + 59) = 7 u + 413
Cost of 13 necklaces = 13 u
Amount that Vanessa had at first
= 7 u + 413 + 13 u
= 20 u + 413
= 20 x 44 + 413
= $1293
Answer(s): $1293
