During a sale, 8 necklaces and 11 bracelets cost $1889. If Julie bought 13 necklaces and 10 bracelets, she would have spent all her money. Each necklace cost $20 more than a bracelet. Find the amount that Julie had at first.
| |
Case 1 |
Case 2 |
| |
Necklaces |
Bracelets |
Necklaces |
Bracelets |
| Number |
8 |
11 |
13 |
10 |
| Value |
1 u + 20 |
1 u |
1 u + 20 |
1 u |
| Total value |
8 u + 160 |
11 u |
13 u + 260 |
10 u |
Cost of 1 bracelet = 1 u
Cost of 11 bracelets = 11 u
Cost of 1 necklace = 1 u + 20
Cost of 8 necklaces = 8 x (1 u + 20) = 8 u + 160
Total cost of 11 bracelets and 8 necklaces
= 11 u + 8 u + 160
= 19 u + 160
19 u + 160 = 1889
19 u = 1889 - 160
19 u = 1729
1 u = 1729 ÷ 19 = 91
Cost of 13 necklaces = 13(1 u + 20) = 13 u + 260
Cost of 10 bracelets = 10 u
Amount that Julie had at first
= 13 u + 260 + 10 u
= 23 u + 260
= 23 x 91 + 260
= $2353
Answer(s): $2353
