During a sale, 10 necklaces and 11 rings cost $2955. If Ivory bought 8 necklaces and 4 rings, she would have spent all her money. Each necklace cost $117 more than a ring. Find the amount that Ivory had at first.
| |
Case 1 |
Case 2 |
| |
Necklaces |
Rings |
Necklaces |
Rings |
| Number |
10 |
11 |
8 |
4 |
| Value |
1 u + 117 |
1 u |
1 u + 117 |
1 u |
| Total value |
10 u + 1170 |
11 u |
8 u + 936 |
4 u |
Cost of 1 ring = 1 u
Cost of 11 rings = 11 u
Cost of 1 necklace = 1 u + 117
Cost of 10 necklaces = 10 x (1 u + 117) = 10 u + 1170
Total cost of 11 rings and 10 necklaces
= 11 u + 10 u + 1170
= 21 u + 1170
21 u + 1170 = 2955
21 u = 2955 - 1170
21 u = 1785
1 u = 1785 ÷ 21 = 85
Cost of 8 necklaces = 8(1 u + 117) = 8 u + 936
Cost of 4 rings = 4 u
Amount that Ivory had at first
= 8 u + 936 + 4 u
= 12 u + 936
= 12 x 85 + 936
= $1956
Answer(s): $1956
