During a sale, 8 bracelets and 6 rings cost $608. If Marion bought 12 bracelets and 2 rings, she would have spent all her money. Each bracelet cost $41 more than a ring. Find the amount that Marion had at first.
| |
Case 1 |
Case 2 |
| |
Bracelets |
Rings |
Bracelets |
Rings |
| Number |
8 |
6 |
12 |
2 |
| Value |
1 u + 41 |
1 u |
1 u + 41 |
1 u |
| Total value |
8 u + 328 |
6 u |
12 u + 492 |
2 u |
Cost of 1 ring = 1 u
Cost of 6 rings = 6 u
Cost of 1 bracelet = 1 u + 41
Cost of 8 bracelets = 8 x (1 u + 41) = 8 u + 328
Total cost of 6 rings and 8 bracelets
= 6 u + 8 u + 328
= 14 u + 328
14 u + 328 = 608
14 u = 608 - 328
14 u = 280
1 u = 280 ÷ 14 = 20
Cost of 12 bracelets = 12(1 u + 41) = 12 u + 492
Cost of 2 rings = 2 u
Amount that Marion had at first
= 12 u + 492 + 2 u
= 14 u + 492
= 14 x 20 + 492
= $772
Answer(s): $772
