During a sale, 9 rings and 3 bracelets cost $1068. If Jaslyn bought 15 rings and 2 bracelets, she would have spent all her money. Each ring cost $36 more than a bracelet. Find the amount that Jaslyn had at first.
|
Case 1 |
Case 2 |
|
Rings |
Bracelets |
Rings |
Bracelets |
Number |
9 |
3 |
15 |
2 |
Value |
1 u + 36 |
1 u |
1 u + 36 |
1 u |
Total value |
9 u + 324 |
3 u |
15 u + 540 |
2 u |
Cost of 1 bracelet = 1 u
Cost of 3 bracelets = 3 u
Cost of 1 ring = 1 u + 36
Cost of 9 rings = 9 x (1 u + 36) = 9 u + 324
Total cost of 3 bracelets and 9 rings
= 3 u + 9 u + 324
= 12 u + 324
12 u + 324 = 1068
12 u = 1068 - 324
12 u = 744
1 u = 744 ÷ 12 = 62
Cost of 15 rings = 15(1 u + 36) = 15 u + 540
Cost of 2 bracelets = 2 u
Amount that Jaslyn had at first
= 15 u + 540 + 2 u
= 17 u + 540
= 17 x 62 + 540
= $1594
Answer(s): $1594