During a sale, 10 bracelets and 4 rings cost $908. If Raeann bought 14 bracelets and 5 rings, she would have spent all her money. Each bracelet cost $60 more than a ring. Find the amount that Raeann had at first.
| |
Case 1 |
Case 2 |
| |
Bracelets |
Rings |
Bracelets |
Rings |
| Number |
10 |
4 |
14 |
5 |
| Value |
1 u + 60 |
1 u |
1 u + 60 |
1 u |
| Total value |
10 u + 600 |
4 u |
14 u + 840 |
5 u |
Cost of 1 ring = 1 u
Cost of 4 rings = 4 u
Cost of 1 bracelet = 1 u + 60
Cost of 10 bracelets = 10 x (1 u + 60) = 10 u + 600
Total cost of 4 rings and 10 bracelets
= 4 u + 10 u + 600
= 14 u + 600
14 u + 600 = 908
14 u = 908 - 600
14 u = 308
1 u = 308 ÷ 14 = 22
Cost of 14 bracelets = 14(1 u + 60) = 14 u + 840
Cost of 5 rings = 5 u
Amount that Raeann had at first
= 14 u + 840 + 5 u
= 19 u + 840
= 19 x 22 + 840
= $1258
Answer(s): $1258
