During a sale, 11 necklaces and 5 bracelets cost $483. If Hilda bought 13 necklaces and 7 bracelets, she would have spent all her money. Each necklace cost $25 more than a bracelet. Find the amount that Hilda had at first.
| |
Case 1 |
Case 2 |
| |
Necklaces |
Bracelets |
Necklaces |
Bracelets |
| Number |
11 |
5 |
13 |
7 |
| Value |
1 u + 25 |
1 u |
1 u + 25 |
1 u |
| Total value |
11 u + 275 |
5 u |
13 u + 325 |
7 u |
Cost of 1 bracelet = 1 u
Cost of 5 bracelets = 5 u
Cost of 1 necklace = 1 u + 25
Cost of 11 necklaces = 11 x (1 u + 25) = 11 u + 275
Total cost of 5 bracelets and 11 necklaces
= 5 u + 11 u + 275
= 16 u + 275
16 u + 275 = 483
16 u = 483 - 275
16 u = 208
1 u = 208 ÷ 16 = 13
Cost of 13 necklaces = 13(1 u + 25) = 13 u + 325
Cost of 7 bracelets = 7 u
Amount that Hilda had at first
= 13 u + 325 + 7 u
= 20 u + 325
= 20 x 13 + 325
= $585
Answer(s): $585
