During a sale, 6 bracelets and 9 necklaces cost $714. If Jaslyn bought 4 bracelets and 12 necklaces, she would have spent all her money. Each bracelet cost $14 more than a necklace. Find the amount that Jaslyn had at first.
| |
Case 1 |
Case 2 |
| |
Bracelets |
Necklaces |
Bracelets |
Necklaces |
| Number |
6 |
9 |
4 |
12 |
| Value |
1 u + 14 |
1 u |
1 u + 14 |
1 u |
| Total value |
6 u + 84 |
9 u |
4 u + 56 |
12 u |
Cost of 1 necklace = 1 u
Cost of 9 necklaces = 9 u
Cost of 1 bracelet = 1 u + 14
Cost of 6 bracelets = 6 x (1 u + 14) = 6 u + 84
Total cost of 9 necklaces and 6 bracelets
= 9 u + 6 u + 84
= 15 u + 84
15 u + 84 = 714
15 u = 714 - 84
15 u = 630
1 u = 630 ÷ 15 = 42
Cost of 4 bracelets = 4(1 u + 14) = 4 u + 56
Cost of 12 necklaces = 12 u
Amount that Jaslyn had at first
= 4 u + 56 + 12 u
= 16 u + 56
= 16 x 42 + 56
= $728
Answer(s): $728
