During a sale, 7 necklaces and 3 bracelets cost $1115. If Kimberly bought 10 necklaces and 3 bracelets, she would have spent all her money. Each necklace cost $65 more than a bracelet. Find the amount that Kimberly had at first.
| |
Case 1 |
Case 2 |
| |
Necklaces |
Bracelets |
Necklaces |
Bracelets |
| Number |
7 |
3 |
10 |
3 |
| Value |
1 u + 65 |
1 u |
1 u + 65 |
1 u |
| Total value |
7 u + 455 |
3 u |
10 u + 650 |
3 u |
Cost of 1 bracelet = 1 u
Cost of 3 bracelets = 3 u
Cost of 1 necklace = 1 u + 65
Cost of 7 necklaces = 7 x (1 u + 65) = 7 u + 455
Total cost of 3 bracelets and 7 necklaces
= 3 u + 7 u + 455
= 10 u + 455
10 u + 455 = 1115
10 u = 1115 - 455
10 u = 660
1 u = 660 ÷ 10 = 66
Cost of 10 necklaces = 10(1 u + 65) = 10 u + 650
Cost of 3 bracelets = 3 u
Amount that Kimberly had at first
= 10 u + 650 + 3 u
= 13 u + 650
= 13 x 66 + 650
= $1508
Answer(s): $1508
