During a sale, 8 bracelets and 10 necklaces cost $1512. If Usha bought 14 bracelets and 2 necklaces, she would have spent all her money. Each bracelet cost $45 more than a necklace. Find the amount that Usha had at first.
| |
Case 1 |
Case 2 |
| |
Bracelets |
Necklaces |
Bracelets |
Necklaces |
| Number |
8 |
10 |
14 |
2 |
| Value |
1 u + 45 |
1 u |
1 u + 45 |
1 u |
| Total value |
8 u + 360 |
10 u |
14 u + 630 |
2 u |
Cost of 1 necklace = 1 u
Cost of 10 necklaces = 10 u
Cost of 1 bracelet = 1 u + 45
Cost of 8 bracelets = 8 x (1 u + 45) = 8 u + 360
Total cost of 10 necklaces and 8 bracelets
= 10 u + 8 u + 360
= 18 u + 360
18 u + 360 = 1512
18 u = 1512 - 360
18 u = 1152
1 u = 1152 ÷ 18 = 64
Cost of 14 bracelets = 14(1 u + 45) = 14 u + 630
Cost of 2 necklaces = 2 u
Amount that Usha had at first
= 14 u + 630 + 2 u
= 16 u + 630
= 16 x 64 + 630
= $1654
Answer(s): $1654
