During a sale, 4 necklaces and 12 bracelets cost $1296. If Linda bought 14 necklaces and 3 bracelets, she would have spent all her money. Each necklace cost $148 more than a bracelet. Find the amount that Linda had at first.
| |
Case 1 |
Case 2 |
| |
Necklaces |
Bracelets |
Necklaces |
Bracelets |
| Number |
4 |
12 |
14 |
3 |
| Value |
1 u + 148 |
1 u |
1 u + 148 |
1 u |
| Total value |
4 u + 592 |
12 u |
14 u + 2072 |
3 u |
Cost of 1 bracelet = 1 u
Cost of 12 bracelets = 12 u
Cost of 1 necklace = 1 u + 148
Cost of 4 necklaces = 4 x (1 u + 148) = 4 u + 592
Total cost of 12 bracelets and 4 necklaces
= 12 u + 4 u + 592
= 16 u + 592
16 u + 592 = 1296
16 u = 1296 - 592
16 u = 704
1 u = 704 ÷ 16 = 44
Cost of 14 necklaces = 14(1 u + 148) = 14 u + 2072
Cost of 3 bracelets = 3 u
Amount that Linda had at first
= 14 u + 2072 + 3 u
= 17 u + 2072
= 17 x 44 + 2072
= $2820
Answer(s): $2820
