During a sale, 10 rings and 4 bracelets cost $1144. If Jane bought 7 rings and 15 bracelets, she would have spent all her money. Each ring cost $99 more than a bracelet. Find the amount that Jane had at first.
| |
Case 1 |
Case 2 |
| |
Rings |
Bracelets |
Rings |
Bracelets |
| Number |
10 |
4 |
7 |
15 |
| Value |
1 u + 99 |
1 u |
1 u + 99 |
1 u |
| Total value |
10 u + 990 |
4 u |
7 u + 693 |
15 u |
Cost of 1 bracelet = 1 u
Cost of 4 bracelets = 4 u
Cost of 1 ring = 1 u + 99
Cost of 10 rings = 10 x (1 u + 99) = 10 u + 990
Total cost of 4 bracelets and 10 rings
= 4 u + 10 u + 990
= 14 u + 990
14 u + 990 = 1144
14 u = 1144 - 990
14 u = 154
1 u = 154 ÷ 14 = 11
Cost of 7 rings = 7(1 u + 99) = 7 u + 693
Cost of 15 bracelets = 15 u
Amount that Jane had at first
= 7 u + 693 + 15 u
= 22 u + 693
= 22 x 11 + 693
= $935
Answer(s): $935
