During a sale, 9 rings and 12 bracelets cost $1602. If Hilda bought 9 rings and 4 bracelets, she would have spent all her money. Each ring cost $87 more than a bracelet. Find the amount that Hilda had at first.
| |
Case 1 |
Case 2 |
| |
Rings |
Bracelets |
Rings |
Bracelets |
| Number |
9 |
12 |
9 |
4 |
| Value |
1 u + 87 |
1 u |
1 u + 87 |
1 u |
| Total value |
9 u + 783 |
12 u |
9 u + 783 |
4 u |
Cost of 1 bracelet = 1 u
Cost of 12 bracelets = 12 u
Cost of 1 ring = 1 u + 87
Cost of 9 rings = 9 x (1 u + 87) = 9 u + 783
Total cost of 12 bracelets and 9 rings
= 12 u + 9 u + 783
= 21 u + 783
21 u + 783 = 1602
21 u = 1602 - 783
21 u = 819
1 u = 819 ÷ 21 = 39
Cost of 9 rings = 9(1 u + 87) = 9 u + 783
Cost of 4 bracelets = 4 u
Amount that Hilda had at first
= 9 u + 783 + 4 u
= 13 u + 783
= 13 x 39 + 783
= $1290
Answer(s): $1290
