During a sale, 11 rings and 4 necklaces cost $1136. If Jaslyn bought 11 rings and 14 necklaces, she would have spent all her money. Each ring cost $31 more than a necklace. Find the amount that Jaslyn had at first.
| |
Case 1 |
Case 2 |
| |
Rings |
Necklaces |
Rings |
Necklaces |
| Number |
11 |
4 |
11 |
14 |
| Value |
1 u + 31 |
1 u |
1 u + 31 |
1 u |
| Total value |
11 u + 341 |
4 u |
11 u + 341 |
14 u |
Cost of 1 necklace = 1 u
Cost of 4 necklaces = 4 u
Cost of 1 ring = 1 u + 31
Cost of 11 rings = 11 x (1 u + 31) = 11 u + 341
Total cost of 4 necklaces and 11 rings
= 4 u + 11 u + 341
= 15 u + 341
15 u + 341 = 1136
15 u = 1136 - 341
15 u = 795
1 u = 795 ÷ 15 = 53
Cost of 11 rings = 11(1 u + 31) = 11 u + 341
Cost of 14 necklaces = 14 u
Amount that Jaslyn had at first
= 11 u + 341 + 14 u
= 25 u + 341
= 25 x 53 + 341
= $1666
Answer(s): $1666
