During a sale, 6 bracelets and 5 rings cost $1298. If Nicole bought 11 bracelets and 8 rings, she would have spent all her money. Each bracelet cost $88 more than a ring. Find the amount that Nicole had at first.
| |
Case 1 |
Case 2 |
| |
Bracelets |
Rings |
Bracelets |
Rings |
| Number |
6 |
5 |
11 |
8 |
| Value |
1 u + 88 |
1 u |
1 u + 88 |
1 u |
| Total value |
6 u + 528 |
5 u |
11 u + 968 |
8 u |
Cost of 1 ring = 1 u
Cost of 5 rings = 5 u
Cost of 1 bracelet = 1 u + 88
Cost of 6 bracelets = 6 x (1 u + 88) = 6 u + 528
Total cost of 5 rings and 6 bracelets
= 5 u + 6 u + 528
= 11 u + 528
11 u + 528 = 1298
11 u = 1298 - 528
11 u = 770
1 u = 770 ÷ 11 = 70
Cost of 11 bracelets = 11(1 u + 88) = 11 u + 968
Cost of 8 rings = 8 u
Amount that Nicole had at first
= 11 u + 968 + 8 u
= 19 u + 968
= 19 x 70 + 968
= $2298
Answer(s): $2298
