During a sale, 5 rings and 6 bracelets cost $1439. If Irene bought 12 rings and 8 bracelets, she would have spent all her money. Each ring cost $136 more than a bracelet. Find the amount that Irene had at first.
| |
Case 1 |
Case 2 |
| |
Rings |
Bracelets |
Rings |
Bracelets |
| Number |
5 |
6 |
12 |
8 |
| Value |
1 u + 136 |
1 u |
1 u + 136 |
1 u |
| Total value |
5 u + 680 |
6 u |
12 u + 1632 |
8 u |
Cost of 1 bracelet = 1 u
Cost of 6 bracelets = 6 u
Cost of 1 ring = 1 u + 136
Cost of 5 rings = 5 x (1 u + 136) = 5 u + 680
Total cost of 6 bracelets and 5 rings
= 6 u + 5 u + 680
= 11 u + 680
11 u + 680 = 1439
11 u = 1439 - 680
11 u = 759
1 u = 759 ÷ 11 = 69
Cost of 12 rings = 12(1 u + 136) = 12 u + 1632
Cost of 8 bracelets = 8 u
Amount that Irene had at first
= 12 u + 1632 + 8 u
= 20 u + 1632
= 20 x 69 + 1632
= $3012
Answer(s): $3012
