During a sale, 11 necklaces and 4 rings cost $1296. If Abi bought 9 necklaces and 2 rings, she would have spent all her money. Each necklace cost $36 more than a ring. Find the amount that Abi had at first.
| |
Case 1 |
Case 2 |
| |
Necklaces |
Rings |
Necklaces |
Rings |
| Number |
11 |
4 |
9 |
2 |
| Value |
1 u + 36 |
1 u |
1 u + 36 |
1 u |
| Total value |
11 u + 396 |
4 u |
9 u + 324 |
2 u |
Cost of 1 ring = 1 u
Cost of 4 rings = 4 u
Cost of 1 necklace = 1 u + 36
Cost of 11 necklaces = 11 x (1 u + 36) = 11 u + 396
Total cost of 4 rings and 11 necklaces
= 4 u + 11 u + 396
= 15 u + 396
15 u + 396 = 1296
15 u = 1296 - 396
15 u = 900
1 u = 900 ÷ 15 = 60
Cost of 9 necklaces = 9(1 u + 36) = 9 u + 324
Cost of 2 rings = 2 u
Amount that Abi had at first
= 9 u + 324 + 2 u
= 11 u + 324
= 11 x 60 + 324
= $984
Answer(s): $984
