Last year, Brandon was 4 times as old as his son, Sean. This year, their total age is 62 years old. How old will Brandon be when he is 2 times as old as Sean?
| |
Brandon |
Sean |
Difference |
Total |
| Before |
4x1 =
4 u |
1x1 =
1 u |
3x1 =
3 u |
|
| Change 1 |
+ 1 |
+ 1 |
|
|
| After 1 |
4 u + 1 |
1 u + 1 |
|
62 |
| Change |
+ ? |
+ ? |
|
|
After 2 |
2x3 =
6 u |
1x3 =
3 u |
1x3 =
3 u |
|
The difference in Ben's age and his son's age always remains unchanged. Make the difference in age the same. LCM of 3 and 1 is 3.
Total age of Brandon and his son this year
= 4 u + 1 + 1 u + 1
= 5 u + 2
5 u + 2 = 62
5 u = 62 - 2
5 u = 60
1 u = 60 ÷ 5 = 12
Brandon's age when he is 2 times as old as Sean
= 6 u
= 6 x 12
= 72
Answer(s): 72
