Bag C contains 50-cent coins and Bag D contains 5-cent coins. There are 18 more coins in Bag D than in Bag C. The amount of money in Bag C is 540¢ more than the amount of money in Bag D. How many total coins are there?
|
Bag C |
Bag D |
Number |
1 u |
1 u + 18 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 90 |
Total value of 50¢ coins in Bag C
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Bag D
= 5 x (1 u + 18)
= 5 u + 90
The amount in Bag C is 540¢ more than Bag D. If another 540¢ is added into Bag D, both Bag C and Bag D will have the same amounts of money.
50 u = 5 u + 90 + 540
50 u - 5 u = 90 + 540
45 u = 630
1 u = 630 ÷ 45 = 14
Total number of coins
= 1 u + (1 u + 18)
= 2 u + 18
= 2 x 14 + 18
= 28 + 18
= 46
Answer(s): 46