Jar Z contains 20-cent coins and Jar A contains 5-cent coins. There are 36 more coins in Jar A than in Jar Z. The amount of money in Jar Z is 255¢ more than the amount of money in Jar A. How many total coins are there?
| |
Jar Z |
Jar A |
| Number |
1 u |
1 u + 36 |
| Value |
20¢ |
5¢ |
| Total value |
20 u |
5 u + 180 |
Total value of 20¢ coins in Jar Z
= 20 x 1 u
= 20 u
Total value of 5¢ coins in Jar A
= 5 x (1 u + 36)
= 5 u + 180
The amount in Jar Z is 255¢ more than Jar A. If another 255¢ is added into Jar A, both Jar Z and Jar A will have the same amounts of money.
20 u = 5 u + 180 + 255
20 u - 5 u = 180 + 255
15 u = 435
1 u = 435 ÷ 15 = 29
Total number of coins
= 1 u + (1 u + 36)
= 2 u + 36
= 2 x 29 + 36
= 58 + 36
= 94
Answer(s): 94
