Tin Can E contains 50-cent coins and Tin Can F contains 10-cent coins. There are 33 more coins in Tin Can F than in Tin Can E. The amount of money in Tin Can E is 470¢ more than the amount of money in Tin Can F. How many total coins are there?
| |
Tin Can E |
Tin Can F |
| Number |
1 u |
1 u + 33 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 330 |
Total value of 50¢ coins in Tin Can E
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Tin Can F
= 10 x (1 u + 33)
= 10 u + 330
The amount in Tin Can E is 470¢ more than Tin Can F. If another 470¢ is added into Tin Can F, both Tin Can E and Tin Can F will have the same amounts of money.
50 u = 10 u + 330 + 470
50 u - 10 u = 330 + 470
40 u = 800
1 u = 800 ÷ 40 = 20
Total number of coins
= 1 u + (1 u + 33)
= 2 u + 33
= 2 x 20 + 33
= 40 + 33
= 73
Answer(s): 73
