Pouch A contains 20-cent coins and Pouch B contains 5-cent coins. There are 22 more coins in Pouch B than in Pouch A. The amount of money in Pouch A is 85¢ more than the amount of money in Pouch B. How many total coins are there?
| |
Pouch A |
Pouch B |
| Number |
1 u |
1 u + 22 |
| Value |
20¢ |
5¢ |
| Total value |
20 u |
5 u + 110 |
Total value of 20¢ coins in Pouch A
= 20 x 1 u
= 20 u
Total value of 5¢ coins in Pouch B
= 5 x (1 u + 22)
= 5 u + 110
The amount in Pouch A is 85¢ more than Pouch B. If another 85¢ is added into Pouch B, both Pouch A and Pouch B will have the same amounts of money.
20 u = 5 u + 110 + 85
20 u - 5 u = 110 + 85
15 u = 195
1 u = 195 ÷ 15 = 13
Total number of coins
= 1 u + (1 u + 22)
= 2 u + 22
= 2 x 13 + 22
= 26 + 22
= 48
Answer(s): 48
