Pouch Y contains 50-cent coins and Pouch Z contains 10-cent coins. There are 20 more coins in Pouch Z than in Pouch Y. The amount of money in Pouch Y is 480¢ more than the amount of money in Pouch Z. How many total coins are there?
| |
Pouch Y |
Pouch Z |
| Number |
1 u |
1 u + 20 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 200 |
Total value of 50¢ coins in Pouch Y
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Pouch Z
= 10 x (1 u + 20)
= 10 u + 200
The amount in Pouch Y is 480¢ more than Pouch Z. If another 480¢ is added into Pouch Z, both Pouch Y and Pouch Z will have the same amounts of money.
50 u = 10 u + 200 + 480
50 u - 10 u = 200 + 480
40 u = 680
1 u = 680 ÷ 40 = 17
Total number of coins
= 1 u + (1 u + 20)
= 2 u + 20
= 2 x 17 + 20
= 34 + 20
= 54
Answer(s): 54
