Jar Y contains 50-cent coins and Jar Z contains 5-cent coins. There are 31 more coins in Jar Z than in Jar Y. The amount of money in Jar Y is 1060¢ more than the amount of money in Jar Z. How many total coins are there?
| |
Jar Y |
Jar Z |
| Number |
1 u |
1 u + 31 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 155 |
Total value of 50¢ coins in Jar Y
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar Z
= 5 x (1 u + 31)
= 5 u + 155
The amount in Jar Y is 1060¢ more than Jar Z. If another 1060¢ is added into Jar Z, both Jar Y and Jar Z will have the same amounts of money.
50 u = 5 u + 155 + 1060
50 u - 5 u = 155 + 1060
45 u = 1215
1 u = 1215 ÷ 45 = 27
Total number of coins
= 1 u + (1 u + 31)
= 2 u + 31
= 2 x 27 + 31
= 54 + 31
= 85
Answer(s): 85
