Jar E contains 50-cent coins and Jar F contains 20-cent coins. There are 15 more coins in Jar F than in Jar E. The amount of money in Jar E is 180¢ more than the amount of money in Jar F. How many total coins are there?
| |
Jar E |
Jar F |
| Number |
1 u |
1 u + 15 |
| Value |
50¢ |
20¢ |
| Total value |
50 u |
20 u + 300 |
Total value of 50¢ coins in Jar E
= 50 x 1 u
= 50 u
Total value of 20¢ coins in Jar F
= 20 x (1 u + 15)
= 20 u + 300
The amount in Jar E is 180¢ more than Jar F. If another 180¢ is added into Jar F, both Jar E and Jar F will have the same amounts of money.
50 u = 20 u + 300 + 180
50 u - 20 u = 300 + 180
30 u = 480
1 u = 480 ÷ 30 = 16
Total number of coins
= 1 u + (1 u + 15)
= 2 u + 15
= 2 x 16 + 15
= 32 + 15
= 47
Answer(s): 47
