Tin Can E contains 50-cent coins and Tin Can F contains 20-cent coins. There are 37 more coins in Tin Can F than in Tin Can E. The amount of money in Tin Can E is 70¢ more than the amount of money in Tin Can F. How many total coins are there?
|
Tin Can E |
Tin Can F |
Number |
1 u |
1 u + 37 |
Value |
50¢ |
20¢ |
Total value |
50 u |
20 u + 740 |
Total value of 50¢ coins in Tin Can E
= 50 x 1 u
= 50 u
Total value of 20¢ coins in Tin Can F
= 20 x (1 u + 37)
= 20 u + 740
The amount in Tin Can E is 70¢ more than Tin Can F. If another 70¢ is added into Tin Can F, both Tin Can E and Tin Can F will have the same amounts of money.
50 u = 20 u + 740 + 70
50 u - 20 u = 740 + 70
30 u = 810
1 u = 810 ÷ 30 = 27
Total number of coins
= 1 u + (1 u + 37)
= 2 u + 37
= 2 x 27 + 37
= 54 + 37
= 91
Answer(s): 91