Jar V contains 50-cent coins and Jar W contains 20-cent coins. There are 16 more coins in Jar W than in Jar V. The amount of money in Jar V is 400¢ more than the amount of money in Jar W. How many total coins are there?
| |
Jar V |
Jar W |
| Number |
1 u |
1 u + 16 |
| Value |
50¢ |
20¢ |
| Total value |
50 u |
20 u + 320 |
Total value of 50¢ coins in Jar V
= 50 x 1 u
= 50 u
Total value of 20¢ coins in Jar W
= 20 x (1 u + 16)
= 20 u + 320
The amount in Jar V is 400¢ more than Jar W. If another 400¢ is added into Jar W, both Jar V and Jar W will have the same amounts of money.
50 u = 20 u + 320 + 400
50 u - 20 u = 320 + 400
30 u = 720
1 u = 720 ÷ 30 = 24
Total number of coins
= 1 u + (1 u + 16)
= 2 u + 16
= 2 x 24 + 16
= 48 + 16
= 64
Answer(s): 64
