Jar W contains 20-cent coins and Jar X contains 5-cent coins. There are 25 more coins in Jar X than in Jar W. The amount of money in Jar W is 160¢ more than the amount of money in Jar X. How many total coins are there?
| |
Jar W |
Jar X |
| Number |
1 u |
1 u + 25 |
| Value |
20¢ |
5¢ |
| Total value |
20 u |
5 u + 125 |
Total value of 20¢ coins in Jar W
= 20 x 1 u
= 20 u
Total value of 5¢ coins in Jar X
= 5 x (1 u + 25)
= 5 u + 125
The amount in Jar W is 160¢ more than Jar X. If another 160¢ is added into Jar X, both Jar W and Jar X will have the same amounts of money.
20 u = 5 u + 125 + 160
20 u - 5 u = 125 + 160
15 u = 285
1 u = 285 ÷ 15 = 19
Total number of coins
= 1 u + (1 u + 25)
= 2 u + 25
= 2 x 19 + 25
= 38 + 25
= 63
Answer(s): 63
