Coin Box J contains 50-cent coins and Coin Box K contains 10-cent coins. There are 32 more coins in Coin Box K than in Coin Box J. The amount of money in Coin Box J is 880¢ more than the amount of money in Coin Box K. How many total coins are there?
| |
Coin Box J |
Coin Box K |
| Number |
1 u |
1 u + 32 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 320 |
Total value of 50¢ coins in Coin Box J
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Coin Box K
= 10 x (1 u + 32)
= 10 u + 320
The amount in Coin Box J is 880¢ more than Coin Box K. If another 880¢ is added into Coin Box K, both Coin Box J and Coin Box K will have the same amounts of money.
50 u = 10 u + 320 + 880
50 u - 10 u = 320 + 880
40 u = 1200
1 u = 1200 ÷ 40 = 30
Total number of coins
= 1 u + (1 u + 32)
= 2 u + 32
= 2 x 30 + 32
= 60 + 32
= 92
Answer(s): 92
