Tin Can V contains 20-cent coins and Tin Can W contains 5-cent coins. There are 20 more coins in Tin Can W than in Tin Can V. The amount of money in Tin Can V is 110¢ more than the amount of money in Tin Can W. How many total coins are there?
| |
Tin Can V |
Tin Can W |
| Number |
1 u |
1 u + 20 |
| Value |
20¢ |
5¢ |
| Total value |
20 u |
5 u + 100 |
Total value of 20¢ coins in Tin Can V
= 20 x 1 u
= 20 u
Total value of 5¢ coins in Tin Can W
= 5 x (1 u + 20)
= 5 u + 100
The amount in Tin Can V is 110¢ more than Tin Can W. If another 110¢ is added into Tin Can W, both Tin Can V and Tin Can W will have the same amounts of money.
20 u = 5 u + 100 + 110
20 u - 5 u = 100 + 110
15 u = 210
1 u = 210 ÷ 15 = 14
Total number of coins
= 1 u + (1 u + 20)
= 2 u + 20
= 2 x 14 + 20
= 28 + 20
= 48
Answer(s): 48
