Jar V contains 20-cent coins and Jar W contains 5-cent coins. There are 16 more coins in Jar W than in Jar V. The amount of money in Jar V is 235¢ more than the amount of money in Jar W. How many total coins are there?
|
Jar V |
Jar W |
Number |
1 u |
1 u + 16 |
Value |
20¢ |
5¢ |
Total value |
20 u |
5 u + 80 |
Total value of 20¢ coins in Jar V
= 20 x 1 u
= 20 u
Total value of 5¢ coins in Jar W
= 5 x (1 u + 16)
= 5 u + 80
The amount in Jar V is 235¢ more than Jar W. If another 235¢ is added into Jar W, both Jar V and Jar W will have the same amounts of money.
20 u = 5 u + 80 + 235
20 u - 5 u = 80 + 235
15 u = 315
1 u = 315 ÷ 15 = 21
Total number of coins
= 1 u + (1 u + 16)
= 2 u + 16
= 2 x 21 + 16
= 42 + 16
= 58
Answer(s): 58