Bag S contains 50-cent coins and Bag T contains 10-cent coins. There are 26 more coins in Bag T than in Bag S. The amount of money in Bag S is 340¢ more than the amount of money in Bag T. How many total coins are there?
| |
Bag S |
Bag T |
| Number |
1 u |
1 u + 26 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 260 |
Total value of 50¢ coins in Bag S
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bag T
= 10 x (1 u + 26)
= 10 u + 260
The amount in Bag S is 340¢ more than Bag T. If another 340¢ is added into Bag T, both Bag S and Bag T will have the same amounts of money.
50 u = 10 u + 260 + 340
50 u - 10 u = 260 + 340
40 u = 600
1 u = 600 ÷ 40 = 15
Total number of coins
= 1 u + (1 u + 26)
= 2 u + 26
= 2 x 15 + 26
= 30 + 26
= 56
Answer(s): 56
