Jar V contains 50-cent coins and Jar W contains 20-cent coins. There are 15 more coins in Jar W than in Jar V. The amount of money in Jar V is 540¢ more than the amount of money in Jar W. How many total coins are there?
|
Jar V |
Jar W |
Number |
1 u |
1 u + 15 |
Value |
50¢ |
20¢ |
Total value |
50 u |
20 u + 300 |
Total value of 50¢ coins in Jar V
= 50 x 1 u
= 50 u
Total value of 20¢ coins in Jar W
= 20 x (1 u + 15)
= 20 u + 300
The amount in Jar V is 540¢ more than Jar W. If another 540¢ is added into Jar W, both Jar V and Jar W will have the same amounts of money.
50 u = 20 u + 300 + 540
50 u - 20 u = 300 + 540
30 u = 840
1 u = 840 ÷ 30 = 28
Total number of coins
= 1 u + (1 u + 15)
= 2 u + 15
= 2 x 28 + 15
= 56 + 15
= 71
Answer(s): 71