Jar F contains 20-cent coins and Jar G contains 5-cent coins. There are 29 more coins in Jar G than in Jar F. The amount of money in Jar F is 170¢ more than the amount of money in Jar G. How many total coins are there?
| |
Jar F |
Jar G |
| Number |
1 u |
1 u + 29 |
| Value |
20¢ |
5¢ |
| Total value |
20 u |
5 u + 145 |
Total value of 20¢ coins in Jar F
= 20 x 1 u
= 20 u
Total value of 5¢ coins in Jar G
= 5 x (1 u + 29)
= 5 u + 145
The amount in Jar F is 170¢ more than Jar G. If another 170¢ is added into Jar G, both Jar F and Jar G will have the same amounts of money.
20 u = 5 u + 145 + 170
20 u - 5 u = 145 + 170
15 u = 315
1 u = 315 ÷ 15 = 21
Total number of coins
= 1 u + (1 u + 29)
= 2 u + 29
= 2 x 21 + 29
= 42 + 29
= 71
Answer(s): 71
