Tin Can D contains 50-cent coins and Tin Can E contains 5-cent coins. There are 36 more coins in Tin Can E than in Tin Can D. The amount of money in Tin Can D is 1125¢ more than the amount of money in Tin Can E. How many total coins are there?
| |
Tin Can D |
Tin Can E |
| Number |
1 u |
1 u + 36 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 180 |
Total value of 50¢ coins in Tin Can D
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Tin Can E
= 5 x (1 u + 36)
= 5 u + 180
The amount in Tin Can D is 1125¢ more than Tin Can E. If another 1125¢ is added into Tin Can E, both Tin Can D and Tin Can E will have the same amounts of money.
50 u = 5 u + 180 + 1125
50 u - 5 u = 180 + 1125
45 u = 1305
1 u = 1305 ÷ 45 = 29
Total number of coins
= 1 u + (1 u + 36)
= 2 u + 36
= 2 x 29 + 36
= 58 + 36
= 94
Answer(s): 94
