Jar R contains 50-cent coins and Jar S contains 10-cent coins. There are 32 more coins in Jar S than in Jar R. The amount of money in Jar R is 760¢ more than the amount of money in Jar S. How many total coins are there?
| |
Jar R |
Jar S |
| Number |
1 u |
1 u + 32 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 320 |
Total value of 50¢ coins in Jar R
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Jar S
= 10 x (1 u + 32)
= 10 u + 320
The amount in Jar R is 760¢ more than Jar S. If another 760¢ is added into Jar S, both Jar R and Jar S will have the same amounts of money.
50 u = 10 u + 320 + 760
50 u - 10 u = 320 + 760
40 u = 1080
1 u = 1080 ÷ 40 = 27
Total number of coins
= 1 u + (1 u + 32)
= 2 u + 32
= 2 x 27 + 32
= 54 + 32
= 86
Answer(s): 86
