Pouch A contains 50-cent coins and Pouch B contains 20-cent coins. There are 23 more coins in Pouch B than in Pouch A. The amount of money in Pouch A is 230¢ more than the amount of money in Pouch B. How many total coins are there?
| |
Pouch A |
Pouch B |
| Number |
1 u |
1 u + 23 |
| Value |
50¢ |
20¢ |
| Total value |
50 u |
20 u + 460 |
Total value of 50¢ coins in Pouch A
= 50 x 1 u
= 50 u
Total value of 20¢ coins in Pouch B
= 20 x (1 u + 23)
= 20 u + 460
The amount in Pouch A is 230¢ more than Pouch B. If another 230¢ is added into Pouch B, both Pouch A and Pouch B will have the same amounts of money.
50 u = 20 u + 460 + 230
50 u - 20 u = 460 + 230
30 u = 690
1 u = 690 ÷ 30 = 23
Total number of coins
= 1 u + (1 u + 23)
= 2 u + 23
= 2 x 23 + 23
= 46 + 23
= 69
Answer(s): 69
