Bag D contains 50-cent coins and Bag E contains 10-cent coins. There are 40 more coins in Bag E than in Bag D. The amount of money in Bag D is 600¢ more than the amount of money in Bag E. How many total coins are there?
| |
Bag D |
Bag E |
| Number |
1 u |
1 u + 40 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 400 |
Total value of 50¢ coins in Bag D
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bag E
= 10 x (1 u + 40)
= 10 u + 400
The amount in Bag D is 600¢ more than Bag E. If another 600¢ is added into Bag E, both Bag D and Bag E will have the same amounts of money.
50 u = 10 u + 400 + 600
50 u - 10 u = 400 + 600
40 u = 1000
1 u = 1000 ÷ 40 = 25
Total number of coins
= 1 u + (1 u + 40)
= 2 u + 40
= 2 x 25 + 40
= 50 + 40
= 90
Answer(s): 90
