Jar S contains 10-cent coins and Jar T contains 5-cent coins. There are 16 more coins in Jar T than in Jar S. The amount of money in Jar S is 55¢ more than the amount of money in Jar T. How many total coins are there?
| |
Jar S |
Jar T |
| Number |
1 u |
1 u + 16 |
| Value |
10¢ |
5¢ |
| Total value |
10 u |
5 u + 80 |
Total value of 10¢ coins in Jar S
= 10 x 1 u
= 10 u
Total value of 5¢ coins in Jar T
= 5 x (1 u + 16)
= 5 u + 80
The amount in Jar S is 55¢ more than Jar T. If another 55¢ is added into Jar T, both Jar S and Jar T will have the same amounts of money.
10 u = 5 u + 80 + 55
10 u - 5 u = 80 + 55
5 u = 135
1 u = 135 ÷ 5 = 27
Total number of coins
= 1 u + (1 u + 16)
= 2 u + 16
= 2 x 27 + 16
= 54 + 16
= 70
Answer(s): 70
