Bag X contains 20-cent coins and Bag Y contains 5-cent coins. There are 37 more coins in Bag Y than in Bag X. The amount of money in Bag X is 220¢ more than the amount of money in Bag Y. How many total coins are there?
| |
Bag X |
Bag Y |
| Number |
1 u |
1 u + 37 |
| Value |
20¢ |
5¢ |
| Total value |
20 u |
5 u + 185 |
Total value of 20¢ coins in Bag X
= 20 x 1 u
= 20 u
Total value of 5¢ coins in Bag Y
= 5 x (1 u + 37)
= 5 u + 185
The amount in Bag X is 220¢ more than Bag Y. If another 220¢ is added into Bag Y, both Bag X and Bag Y will have the same amounts of money.
20 u = 5 u + 185 + 220
20 u - 5 u = 185 + 220
15 u = 405
1 u = 405 ÷ 15 = 27
Total number of coins
= 1 u + (1 u + 37)
= 2 u + 37
= 2 x 27 + 37
= 54 + 37
= 91
Answer(s): 91
